| CorrectDOY {greenbrown} | R Documentation |
This function corrects a time series with days-of-years (e.g. start of growing season). For example, if the start of season occurs in one year at the end of the calendar year (doy > 305) and in another year at the beginning (doy < 60), the DOYs are corrected so that all values occur at the beginning of the year (e.g. negative DOYs will be produced) or at the end of the year (e.g. DOY > 365 will be produced). This function is applied in Phenology after phenology detection on sos, eos, pop and pot time series (see examples).
CorrectDOY(doy, check.outliers = TRUE)
doy |
a vector or time series representing DOYs |
check.outliers |
Set outliers to NA after correction? Outliers are defined here as: doy < (median - IQR*2) | doy > (median + IQR*2)) |
a vector or time series
Matthias Forkel <matthias.forkel@geo.tuwien.ac.at> [aut, cre]
# imagine the following start of season DOYs in 10 years sos <- ts(c(15, 10, 12, 8, 10, 3, 362, 2, 1, 365), start=1982) plot(sos) # Visually, there seems to be big differences in the start of season. However, # there is actually only one day between the last two values (DOY 1 = 1st January, # DOY 365 = 31st December). Trend calculation fails on this time series: plot(Trend(sos), ylab="SOS") # The DOY time series needs to be corrected to analyze # the true differences between days. sos2 <- CorrectDOY(sos) plot(Trend(sos2), ylab="SOS") # The correction now allows trend analysis. # Negative DOYs indicate days at the end of the previous year! # other example sos <- ts(c(5, 12, 15, 120, 363, 3, 362, 365, 360, 358), start=1982) plot(sos) # one value seems like an outlier sos2 <- CorrectDOY(sos) plot(Trend(sos2), ylab="SOS") # The outlier is removed. # DOYs > 365 indicate days in the next year!